# When you throw a non-uniform object through the air, most points on it follow complex paths. Only the center of mass follows a parabolic trajectory.

Once you throw a non-uniform object by the air, most factors on it comply with complicated paths. Solely the middle of mass follows a parabolic trajectory.

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1. repairedcrab493 says:

But the trajectory of any particle can be described as combined motion of the COM and rotation about the COM.

2. danielm8 says:

This holds true for throwing several separate objects together. Their centre of mass will take a parabolic trajectory, though the objects will likely fly apart

3. ManikMedik says:

I don’t know, all those paths look pretty real to me

4. Helioxsparrow says:

BTW Thor called

5. broodfood says:

Th eres a live-action gif of this somewhere on the internet.

6. Virtualization_Freak says:

Well, this at least helps explain how things like axes are not that hard to sink.

There’s a relatively very large amount of time the head (more precisely, the bit) is in a position to sink into the target compare to when it is not.

7. StinkyBrittches says:

I used to be pretty good at throwing a sledgehammer up in the air and flipping it around. I coukd flip it forwards and backwards, three times around, even behind my back. I remember I always liked flipping hammers and tennis rackets, and so when I read ‘Electric Kool-Aid Acid Test’ and Neal Cassidy was flipping sledgehammers around, I knew I had to get in on that. I should start again when it gets warm!

8. rice_jabroni says:

This has nothing to do with the uniformity of the object. A non-uniform hammer can be thrown in such a way to not rotate in the air, giving every particle in it a parabolic trajectory. A uniform spherical ball can be thrown with spin so that only the center of mass has a parabolic trajectory, and every particle rotates about it.

9. alabasterhelm says:

Maybe rename ‘complex’ to complicated? A complex path has other implications in physics, like for wave motion and behavior.

10. Dogeek says:

I’m wondering, if you were to “straighten” the blue and red trajectories (project them on the parabola), would they be cycloids of the same frequency ? Same Amplitude ? Both ? None ?

11. baldcarlos236 says:

r/oddlysatisfying